in reply to Accessing $a and $b of 'sort' across package boundaries
Update: this answers the wrong question. I didn't read the question. Shame on me. Sorry.
Go see what the pure-perl version of
&List::Util::reduce does.
It aliases the $a and $b in the
scope of the caller to temporary scalars. I think that's
faster then reading the original scalars. The best way would
probably be if you make lexical aliases to those scalars,
but that's out of question in a pure perl implementation
which is used as a failback for the XS version.
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