in reply to Passing a file handle to a sub. I still don't get it.

From perlop

If what the angle brackets contain is a simple scalar variable (e.g., <$foo>), then that variable contains the name of the filehandle to input from, or its typeglob, or a reference to the same. For example: 

      $fh = \*STDIN;
      $line = <$fh>;

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If what's within the angle brackets is neither a filehandle nor a simple scalar variable containing a filehandle name, typeglob, or typeglob reference, it is interpreted as a filename pattern to be globbed, and either a list of filenames or the next filename in the list is returned, depending on context.

the lowliest monk

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Re^2: Passing a file handle to a sub. I still don't get it.
by derby (Abbot) on Jun 09, 2005 at 19:24 UTC

    tlm is correct. So you need to do the following: 

    sub from_handle {
    my $self = shift;
    my %opts = @_;
    my $fh = $opts{-handle};
    while (<$fh>) {
        #... and here we're supposed to read from FH
    }
}

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    -derby
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[d/l]

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