Re^2: Converting multiple spaces to nbsp

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Re^3: Converting multiple spaces to nbsp by ikegami (Patriarch) on Jun 17, 2005 at 14:59 UTC
oo! That's unexpected! I didn't realize that the previous substitution failed to affect `(?<=...)`. `s/(?<=\s)\s/ /g` had occured to me, but I had dismissed it. ++! `local $\ = "\n"; local $_ = ' '; s/(?<=\s)\s/ /g; print; print($_ eq '    ' ? 'correct' : 'wrong'); __END__     correct` [download]	[reply] [d/l] [select]
Re^4: Converting multiple spaces to nbsp by Smylers (Pilgrim) on Jun 17, 2005 at 15:17 UTC
oo! That's unexpected! I didn't realize that the previous substitution failed to affect ... If you think about it, it has to be that way: otherwise you could end up subsituting out something that you've just put in there earlier in the same subtitution, and something like `s/und/underground/g` would get stuck in an infinite loop. But it doesn't matter whether using the already-replaced text would enable further substitutions or prevent existing ones; in neither case is it taken into account. Smylers	[reply] [d/l]
Re^5: Converting multiple spaces to nbsp by ikegami (Patriarch) on Jun 17, 2005 at 15:27 UTC
something like `s/und/underground/g` would get stuck in an infinite loop. No, because the position variable changes. For in-place substitution, it would move by `length('underground')`. Otherwise, it would move by `length('und')`. I made the assumption that the substitution was done in place (since the syntax seems to imply it). You've shown me that's not the case, but it could have been written that way. (Although magic variables would need to be treated specially.)	[reply] [d/l] [select]