Sure it does. the parentheses around 2 + 2 make print behave as a function, so the statement parses as:

"print the result of 2 + 2 (4) and multiply the result of print (1) times 5. That last result is discarded, because it is is void context. You can see how is is parsed:

perl -MO=Deparse -e 'print (2 + 2) * 5'
print(4) * 5;
-e syntax OK
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