Re: pg 246 of programming perl

Change it into,

$a1 = $hashrefA->{'Adam'};

Now you will be getting the correct output.

Prasad

Comment on Re: pg 246 of programming perl Download Code

Replies are listed 'Best First'.
Re^2: pg 246 of programming perl by jbrugger (Parson) on Jun 28, 2005 at 05:45 UTC
Correct!, Since you want to 'learn references', what prasadbabu did, was dereferencing, so $a1 actually holds it's own copy of the value derederendec from the hash. "We all agree on the necessity of compromise. We just can't agree on when it's necessary to compromise." - Larry Wall.	[reply]