in reply to Debug and workaround help

Since you placed 
my $str2Brepl = $`;

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$str2Brepl becomes the same as $string.
perhaps you mean 
my $str2Brepl = $1;

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since you placed brackets around the matching regexp?

"We all agree on the necessity of compromise. We just can't agree on when it's necessary to compromise." - Larry Wall.

In Section Seekers of Perl Wisdom