in reply to Re^2: Regular Expression Help
in thread Regular Expression Help

Sure! Basically if you take where we started : $u = ('0' x (6-length($u))).$u; we can break this up into multiple statements:
$length_of_u = length($u); # how long is this string? $how_many_characters_short = 6-$length_of_u; # how far are we from ha +ving 6 characters? $padding = '0' x $how_many_characters_short; # this will give us as ma +ny 0's as $how_many_characters_short is long (e.g. if it is 4 - it gi +ves us '0000') $u = $padding.$u; # concatenate them together... finished!
HTH!

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Re^4: Regular Expression Help
by Anonymous Monk on Jun 28, 2005 at 18:01 UTC
    Thank you all for the big HELP!!!!