in reply to Re^2: How will you use state declared variables in Perl6?
in thread How will you use state declared variables in Perl6?
I don't think that's the type of closure BrowserUk is referring to. Think more of this perl 5 code:
Each time you call genclosure, you get a new closure, a new state variable. You don't reuse the previously existing state variable.sub genclosure { my $bar; return sub { $bar++; } }
So I would have to agree with BrowserUk's "very carefully" statement. The same as I would use your perl5 (global) closure code - very carefully. That said, I have probably about a half-dozen or so places where I need or want to cache data globally in my projects at work, so this would be very nice syntactical sugar for that. However, I also generate a few closures where this new idea could easily bite a junior programmer in the arse when they wonder why their data isn't returning properly. ("How did that counter get so high already?")
That said, I also generally avoided static in C as well, so that's not really surprising for me. After all, one generally looks at programming tasks from the basis of their experience - if it looks like a nail, that may be because all you have is a hammer.
Update: TimToady's response has cleared things up a bit, thankfully. It was looking a bit grim for state - although there is still some care to be taken. I'll have to think if I can figure out where I'd use this feature, if anywhere.
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Re^4: How will you use state declared variables in Perl6?
by revdiablo (Prior) on Jul 08, 2005 at 22:02 UTC | |
by TimToady (Parson) on Jul 08, 2005 at 22:27 UTC | |
by Limbic~Region (Chancellor) on Jul 08, 2005 at 22:34 UTC | |
by BrowserUk (Patriarch) on Jul 08, 2005 at 22:29 UTC |