sorry yes,
# input 2
xxx
yyyy
1
so with $/ set to # input it would be possible to do a pattern search and print the match?
| [reply] |
yes, that's why i suggested it .. I would (you ignored my questioned about providing code, so i'll continue just guiding with pesudo code until you have something to work from) set $/, then loop through the 'lines' (which will contain multiple \n newlines). During this loop, split on newline to get your array of 4 lines. Note the first one will be just a number (the remainder of the '# input 3' line) and the last one will be '# input ' ($/).
| [reply] [d/l] [select] |
# input 2
xxx
yyy
1
| [reply] [d/l] |
while (<FH>) {
local $/ = '# input';
if (m/1ord/) {
print "$/\n";}
}
this prints the local variable, how can i adjust it to print the enitre # input line? | [reply] [d/l] |