How can I create an array that holds number of variables with values?

Anonymous Monk has asked for the wisdom of the Perl Monks concerning the following question:

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Re: How can I create an array that holds number of variables with values? by runrig (Abbot) on Dec 20, 2000 at 06:13 UTC
my @array = map {0} 0..19;	[reply]
Re: Answer: How can I create an array that holds number of variables with values? by I0 (Priest) on Dec 20, 2000 at 12:24 UTC
`my @array = (0)x20;`	[reply] [d/l]
Re: How can I create an array that holds number of variables with values? by Russ (Deacon) on Dec 27, 2000 at 03:36 UTC
Your question almost answers itself `my @var = (43, 60, 1..18); # Later... print $var[1], $var[14];` [download] Use an array instead of multiple, distinct variables. turnstep is right, you don't have to initialize all the variables to zero, just create them where you need them, giving a value at that time. runrig's code (`my @array = map {0} 0..19`) works fine here, as well.	[reply] [d/l]
Re: How can I create an array that holds number of variables with values? by turnstep (Parson) on Dec 26, 2000 at 08:22 UTC
Also keep in mind that you may not need to initialize them at all - perl can usually figure out what you want to do. For example `my $var1; $var1++; print "Var1 is now $var1\n"; my $var2; $var2 = "Foobar"; print "Var2 is now $var2\n";` [download] Both of the above will work fine. The values start out undefined, and in most cases (but not all) they do not need an explicit initialization.	[reply] [d/l]
Re: How can I create an array that holds number of variables with values? by runrig (Abbot) on Dec 20, 2000 at 06:15 UTC
Or do you mean: `my @array = \my ($var1, $var2, $var3); $$_ = 0 for @array;` [download] Originally posted as a Categorized Answer.	[reply] [d/l]
Re: How can I create an array that holds number of variables with values? by I0 (Priest) on Dec 20, 2000 at 09:13 UTC
`${"var$_"}=0 for(1..20); #but why aren't you using @var[1..20] ?` [download] Originally posted as a Categorized Answer.	[reply] [d/l]
Re: How can I create an array that holds number of variables with values? by Anonymous Monk on Dec 20, 2000 at 06:45 UTC
let me put it in that way: I want to use these variables later in my program rather initializing like this: $var1=0; $var2=0; $var3=0; How can I define an array, so that I can use these variables to assign them later something else ? (i.e: $var1= 43; $var2 = 60; etc... Originally posted as a Categorized Answer.	[reply]