in reply to Array - Reading frame problem

I'm not sure I understand you're question. Do you want to create an array so that each element in the array contains exactly one character, in sequence, from a string? That's pretty simple with split: 
my $sequence = "1234567890";

my @chrsequence = split //, $sequence;

print "array has " . scalar @chrsequence . " elements: @chrsequence\n"
+;

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The first argument to split in this case is an empty regex, which happens to have the effect of splitting the input string at every character.

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Re^2: Array - Reading frame problem
by Nadiah (Novice) on Jul 16, 2005 at 15:33 UTC

    Haha :) thanks graff.. but is it possible to just display the sequence from position 1 onwards and right to the end? (excluding position 0)

[reply]
      You just need to learn more of the basics of perl syntax. There are lots of ways to do whatever you want with any subset of array elements: 
      print "$_\n" for ( @array[1..$#array] );

# which is the same as:

for my $i ( 1 .. $#array ) {
    print "$array[$i]\n";
}

# and

$" = "\n";
print "@array[1..$#array]\n";

      [download]
[reply]
[d/l]
      It is, using the slice notation already mentioned above. 
      my $sequence = "1234567890";

my @chrsequence = (split //, $sequence)[1..length($sequence)-1];

print "array has " . scalar @chrsequence . " elements: @chrsequence\n"
+;

      [download]


      holli, /regexed monk/
[reply]
[d/l]

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