Once you have the file name in a var like:

$filename = 'aa22200010001.png';
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You can use either:

$filename =~ s/(\d{3})(\d{6})(\d{2})/sprintf("%03d%06d%02d", $1,$2+1,$
+3)/e;
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Or (as pointed by BrowserUK):

$filename =~ s/(\d{11})/$1 + 100/e;
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Just note that if your file name var contains the path to the file, and one of the directories in the path contains a similar name (ie. eleven consecutive digits, as in: '/tmp/0123456789019/22200010001.png'), you will have to modify the regexp to take it into account and the replacement part will/may not be so simple.