in reply to Re: Scalar in Method Call
in thread Scalar in Method Call
The no strict 'refs' is unnecessary here, since you aren't dealing with references of any sort. The code will run just fine under strict refs.no strict 'refs'; # because this isn't very strict my $temp_obj = "Foo::$type"->new();
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Re: Re: Re: Scalar in Method Call
by Fastolfe (Vicar) on Dec 22, 2000 at 22:13 UTC |