Re^2: Using undef scalar as arrayref

Ack, you're right about what you noticed about line 5. I goofed. You're also right about the defined test.

The only caveat i can think of is that if the $arrayref got set to an empty arrayref, i'd still not want to do the if conditional (in this situation). So i think the final will be:

   if ( $arrayref && @$arrayref ) {
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which will throw an exception if its not an arrayref.

I use the most powerful debugger available: print!

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Re^3: Using undef scalar as arrayref by Joost (Canon) on Aug 12, 2005 at 20:44 UTC
if you're doing the `for (@arrayref) { ... }` as the only statement within the if() test, you don't have to do the `if (@$arraytest) part`; if the array is empty, the code within in the for() loop won't be executed. "What should it profit a man, if he should win a flame war, yet lose his cool?"	[reply] [d/l] [select]
Re^4: Using undef scalar as arrayref by shemp (Deacon) on Aug 12, 2005 at 21:07 UTC
Actually the if is separate from the loop. If there are any elements in the arrayref a flag needs to be set for later that is separate from what is happening in the loop. So its something like this: `if ( $arrayref && @$arrayref ) { # set the flag } ... foreach my $element (@$arrayref) { # do stuff }` [download] Of course i could set it in the loop, but then its being set multiple times. I use the most powerful debugger available: print!	[reply] [d/l]