Re: to convert 16 dig hex to dec

print hex $value;
[download]

Update: Nevermind this throws a warning:

Integer overflow in hexadecimal number

A way without warnings:

perl -Mbigint -wle 'print 0x9DBE062CB1F34287'

Please, please have a look at the documentation search engine.

-- Frank

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Re^2: to convert 16 dig hex to dec by QM (Parson) on Sep 01, 2005 at 15:41 UTC
`perl -Mbigint -wle 'print 0x9DBE062CB1F34287'` [download] Shouldn't that be: `perl -MMath::Bigint -wle 'print 0x9DBE062CB1F34287'` [download] or is there some new namespace I'm not aware of? Update: I didn't look carefully enough. And I was cross-pollinated with: `perl -MMath::Bigint -wle 'print Math::BigInt->new(q/0x9DBE062CB1F34287 +/)'` [download] -QM -- Quantum Mechanics: The dreams stuff is made of	[reply] [d/l] [select]
Re^3: to convert 16 dig hex to dec by lidden (Curate) on Sep 01, 2005 at 16:57 UTC
Try it. And read "perldoc bigint"	[reply]
Re^4: to convert 16 dig hex to dec by QM (Parson) on Sep 01, 2005 at 18:52 UTC
Of course! Curse my narrow-minded field of view. -QM -- Quantum Mechanics: The dreams stuff is made of	[reply]
Re^2: to convert 16 dig hex to dec by Anonymous Monk on Sep 01, 2005 at 10:39 UTC
I am getting an overflow error Integer overflow in hexadecimal number at hextodec.pl line 8. This is the output 1.13665292985635e+019 I need the output as not in exponential notation but string and I have tried `$dec = hex $hex; printf "%s", $dec;` [download]	[reply] [d/l]