in reply to Listing Files in a Directory (Translation From Shell Script)
There would be an easier way to do that in sed or awk!
#1 ... sed -e "s/.*([FGH]):\\backup\\/\1:\\backup\\ /" < cat.txt > catall #2 ... # (bourne shell syntax, sorry) for d in F G H; do awk '/_/{print "'$d'":\\backup\\" $5 } < ${d}dir.txt done > dirall #3 ... could have done this above by piping through sort. #4 & 5 ... diff -u dirall.srt catall.src | sed -e '/---/d' -e '/^[^-]/d' -e 's/-/ +/g' -e 's/^/del /' > delfile.bat
But, to answer your question, yes, using some hashes, you could figure this out and even unlink them all directly without a batch file.
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