Re: Shortcut operator for $a->{'b'}=$b if $b;

What is the correlation between 'b' and $b? Is one used to derive the other? If so, then map may help.

$a = {
    map {
        $val = some_derivation($_)
            ? ( $_ => $val ) 
            : ()
    } qw(a b c)
};
[download]

Ivan Heffner
Sr. Software Engineer, DAS Lead
WhitePages.com, Inc.

Comment on Re: Shortcut operator for $a->{'b'}=$b if $b; Select or Download Code

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Re^2: Shortcut operator for $a->{'b'}=$b if $b; by rokadave (Sexton) on Sep 20, 2005 at 16:40 UTC
No correlation at all. This all started when I discovered the \|\|= operator, which test the assignee for truth, upon false assigns the assignor. I wanted to test the other side, and assign upon false. I think my answer is no.	[reply]
Re^3: Shortcut operator for $a->{'b'}=$b if $b; by ikegami (Patriarch) on Sep 20, 2005 at 17:02 UTC
"assigns the assignor"? Every definition I can find for "assignor" defines it as the person (or in the case operator) who does the assignment. In other words, "=" is the assignor, not "$b". The standard terminology for assignments is "lvalue" for the variable receiving the value (which is usually on the left) and "rvalue" for the value being copied (which is usually on the right).	[reply]