Re^2: Shortcut operator for $a->{'b'}=$b if $b;

in reply to Re: Shortcut operator for $a->{'b'}=$b if $b;
in thread Shortcut operator for $a->{'b'}=$b if $b;

What's the for doing, there? Doesn't this work?

~~$b and $a->{'b'} = $b~~

edit: Doesn't solve the problem fully.

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Re^3: Shortcut operator for $a->{'b'}=$b if $b; by merlyn (Sage) on Sep 20, 2005 at 16:48 UTC
I thought the point was that $b was standing in for something very complex or impossible to repeat for calculation. -- Randal L. Schwartz, Perl hacker Be sure to read my standard disclaimer if this is a reply.	[reply]
Re^4: Shortcut operator for $a->{'b'}=$b if $b; by chester (Hermit) on Sep 20, 2005 at 16:50 UTC
Ah, I see. My mistake.	[reply]
Re^3: Shortcut operator for $a->{'b'}=$b if $b; by ikegami (Patriarch) on Sep 20, 2005 at 16:48 UTC
foreach loops sets $_ to refer to the current value in the list which is being iterated. In this case, the list consists solely of $b. Your expression is equivalent, but it's not an acceptable answer since the question was about removing the need for using $b twice.	[reply]

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