in reply to Initialization of arrays
The left is an array slice; it's expecting a list on the right. The "list" you gave it is essentially like (1, undef, undef). So only $x[1] is getting a value here. You could write it like:
@x[1..3] = (1,1,1)
For this:
for($y=0; $y!=@x; $y++)You should generally avoid the C-style for. You can rewrite it like this:
for my $y (0..$#x)
Also to easily view the contents of your array without having to loop, you may look into Data::Dumper.
edit: Fixed as per [id://ikegami]'s reply
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Re^2: Initialization of arrays
by ikegami (Patriarch) on Sep 22, 2005 at 14:02 UTC | |
by radiantmatrix (Parson) on Sep 22, 2005 at 14:28 UTC | |
by ikegami (Patriarch) on Sep 22, 2005 at 14:39 UTC | |
by ambrus (Abbot) on Sep 23, 2005 at 16:24 UTC | |
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Re^2: Initialization of arrays
by Tanktalus (Canon) on Sep 22, 2005 at 14:53 UTC |