Radian and other monks ,

Thanks for all those superb answers. I would like to extend a specail thanks to radian as he/she took time to answer why it happens. Never will I get that doubt again.

Well now after learning from the answer given by you people, I am eager to know without giving local $| = 1; in the following code...

   print 'processing';
   for (1..5) {
      print ".\n";
      sleep 1;
   }
[download]

it works well.

I tried it out for "\t" it does not flush . Why is such a behaviour ? what is unique about "\n"?

rgrds

prad