in reply to Re: Substitute 'bad words' with 'good words' according to lists
in thread Substitute 'bad words' with 'good words' according to lists
I think the original code is not necessarily inefficient.I feel the performance depends on number of words your split returns.. Here is a benchmark of the original (added keys which was missing). I have modifed the txt to be 100 times the original one.
Again the story could be different when you have way too many replacements and fewer words.
#!/usr/bin/perl use strict; use warnings; use Benchmark qw (:all); my $txt = "ugly anotherugly " x 100; # print $txt,$/; sub pg { my %words = ( ugly => 'ug**', anotherugly => 'anot*******', ); my @words = split / /, $txt; # largely simplified, you have to cou +nt ,.:; etc for my $i (0 .. $#words) { $words[$i] = $words{$words[$i]} if (exists($words{$words[$ +i]})) } # print join(' ', @words),$/; } sub orig { my %words = ( ugly => 'ug**', anotherugly => 'anot*******', ); $txt =~ s/$_/$words{$_}/g foreach keys(%words); # print $txt,$/; } my $test = {'pg' => \&pg, 'Original' =>\&orig,}; my $result = timethese(-10,$test ); cmpthese($result);
Output
Benchmark: running Original, pg for at least 10 CPU seconds... Original: 11 wallclock secs (10.86 usr + 0.00 sys = 10.86 CPU) @ 43 +770.26/s (n=475345) pg: 11 wallclock secs (10.68 usr + 0.00 sys = 10.68 CPU) @ 43 +28.46/s (n=46228) Rate pg Original pg 4328/s -- -90% Original 43770/s 911% --
NOTE: I removed the join from your code just to show the looping differences.
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Re^3: Substitute 'bad words' with 'good words' according to lists
by pg (Canon) on Sep 26, 2005 at 05:14 UTC |