Re: Increment/Decrement Operator with Strings

The operator works just fine on chars:

# perl -e '$char = "a"; print $char++, $/ for 1..26'
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update: from perlop: "... The auto-increment operator has a little extra builtin magic to it. If you increment a variable that is numeric, or that has ever been used in a numeric context, you get a normal increment. If, however, the variable has been used in only string contexts since it was set, and has a value that is not the empty string and matches the pattern "^[a-zA-Z]*[0-9]*\z/", the increment is done as a string, preserving each character within its range ..."
Nowhere is said the same about the auto-decrement operator, so why should someone expect similar behaviour?

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Re^2: Increment/Decrement Operator with Strings by holli (Abbot) on Sep 27, 2005 at 08:37 UTC
Of course. But that is not the question. The OP asks about the decrement operator, not the increment. holli, /regexed monk/	[reply] [d/l]