in reply to Re: Dynamic regex assertions, capturing groups, and parsers: joy and terror
in thread Dynamic regex assertions, capturing groups, and parsers: joy and terror

The result of (??{ print $1 }) is 1 because print() succeeded in writing to STDOUT. The regex that was then compiled by (??{ ...}) was "1" which then failed. So the (.) advanced over every character and printed them individually. The proper thing to do here would have been (?{ ... }) which will not affect regex matching.

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Re^3: Dynamic regex assertions, capturing groups, and parsers: joy and terror
by demerphq (Chancellor) on Oct 04, 2005 at 09:13 UTC

    Doh. Of course. I knew that the print returning 1 failed the match, but i didn't put two and two together to realize that was why all of the chars were printed. And I've used this technique deliberately before too. /gah.

    Thanks for the clue-by-four. :-)

    ---
    $world=~s/war/peace/g

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