Re: calling a hash

I think they are suggesting you should verify $bob has something in it. If you don't put a value in $bob, it creates a hash entry with the empty string. If you want a hash entry with the string 'bob', don't put the $ in front of it.

I think this would explain your results. Printing $random_name{$bob} is actually $random_name{''} and you are probably entering the string 'bob' at the prompt.

Try this to verify what you have in %random_name:

use Data::Dumper;

print Dumper( \%random_name );
[download]

Comment on Re: calling a hash Download Code

Replies are listed 'Best First'.
Re^2: calling a hash by Anonymous Monk on Oct 04, 2005 at 13:26 UTC
no sorry not the person who posted earlier. but i have resolved the problem, removing the $ in the hash corrected it Thanks for all of your help	[reply]
Re^3: calling a hash by blazar (Canon) on Oct 04, 2005 at 13:37 UTC
Indeed this is a situation in which turning on warnings would have solved the problem for you: `$ perl -we '%a=($bob => "foo")' Name "main::a" used only once: possible typo at -e line 1. Name "main::bob" used only once: possible typo at -e line 1. Use of uninitialized value in list assignment at -e line 1.` [download] See in particular the last line. But then if had also turned on strict `$ perl -Mstrict -e 'my %a=($bob => "foo")' Global symbol "$bob" requires explicit package name at -e line 1. Execution of -e aborted due to compilation errors.` [download] So, to put it briefly: do it!	[reply] [d/l] [select]