Re^4: stripped punctuation

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Re^5: stripped punctuation by fishbot_v2 (Chaplain) on Oct 06, 2005 at 21:45 UTC
from perlre: `A "\w" matches a single alphanumeric character (an alphabetic character, or a decimal digit) or "_"...` [download] Thus your earlier use of `[^\w\d]` had the set of digits in it twice, which suggested to me that you thought that `\w` means `[A-Za-z]`. `[^\w\d]` works, but is redundant and equivalent to `\W` Update: You asked what the speed difference between the two passes and one pass: `s/(?:^\W+)\|(?:\W+$)//g; # versus s/\W+$//g; s/^\W+//g; # my unscientific benchmark Rate single_pass two_pass single_pass 15829/s -- -11% two_pass 17737/s 12% --` [download] Doing it in two passes seems to be about 10-15% faster.	[reply] [d/l] [select]
Re^5: stripped punctuation by Nkuvu (Priest) on Oct 06, 2005 at 21:50 UTC
The \w means "any alphanumeric character or underscore." So in your regex, where you have `[^\w\d]` it's a bit redundant. \w can be replaced by `[a-zA-Z0-9_]` so you're writing `[a-zA-Z0-9_0-9]` in the regexen above. Also note that since \w includes the underscore you're matching more than what you say you want.	[reply] [d/l] [select]