Re: Regex Question

A little bit of lookahead/lookbehind should do it:

s/(?<!\n)\n(?!\n)//g;
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If that seems overly complex, then look for runs of newlines, and don't touch the ones that aren't isolated:

s/(\n+)/$1 eq "\n" ? "" : $1/eg;
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Re: Re: Regex Question by salvadors (Pilgrim) on Jan 08, 2001 at 00:18 UTC
A bit of benchmarking shows that the first is about twice as fast as the second, and about three times faster than my verison... I really must get around to reading the regex book... it's been sitting on my desk for months now. Tony	[reply]