in reply to next'ing out of a "foreach" loop within a subroutine
Is there a better way to do this?
A better way, in my opinion, would be to have the return value of routine indicate whether the for loop should move onto the next value.
foreach $row (@array) { next unless routine($row); # more code here } sub routine { if ($row != '10') { print "stuff"; return 1; } else { return 0; } }
A minor issue with your code as posted: You cannot say $row != '10'. You are using numeric equality against a string. The correct technique is to either compare against a number $row != 10 or compare using string equality $row ne '10'.
You can get Perl to help you with looking out for problems like this if you have warnings switched on. To enable them, add a use warnings; somewhere in the file.
• another intruder with the mooring in the heart of the Perl
|
|---|
| Replies are listed 'Best First'. | |
|---|---|
|
Re^2: next'ing out of a "foreach" loop within a subroutine
by sauoq (Abbot) on Oct 30, 2005 at 21:04 UTC |