Re^2: Looping backwards through two arrays at once?

From the belly I would have said that

for my $i (reverse 0..$#a)
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would cast the list into existance, but as it seems that isn't the case (Perl 5.8).

holli, /regexed monk/

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Re^3: Looping backwards through two arrays at once? by ikegami (Patriarch) on Nov 04, 2005 at 19:07 UTC
Actually, it does cast the list into existance, even in 5.8. I mentioned this elsewhere in this thread. This thread has a discussion on this issue.	[reply]