(tye)Re: Removing characters

Just for fun, I'll assume that I got the output from "man" and someone else has removed the backspaces for me so I want to remove the duplicates... And based on my experience, I may end up with tripled or quadrupled letters as well.

You could do pretty well by finding "words" that contain only doubled letters and modifying those. But a "good" way to do this hasn't popped into my brain yet...

my $inWord= "[-\\w'(),]";
my $notWord= "[^-\\w'(),]";
s#($notWord)(($inWord)\3(?:$inWord)*($inWord)\4)($notWord)#
    my( $pre, $word, $post )= ( $1, $2, $5 );
    my $len= length($word);
    for(  $word =~ /(.)(\1*)/g  ) {
        $len= length($2)  if  length($2) < $len;
    }
    $word =~ s/(.)\1{$len}/$1/g    if  0 < $len;
    $pre . $word . $post;
#ge
[download]

Like I said, that doesn't seem like a great way to do it (untested as well). :-}

- tye (but my friends call me "Tye")

Comment on (tye)Re: Removing characters Download Code

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Re: (tye)Re: Removing characters by chipmunk (Parson) on Jan 09, 2001 at 04:03 UTC
Here's another way of doing it, inspired by your code: `my $word = q{-\w'(),}; s{ (^\|[^$word]) ( (?:([$word])\3)+ ) (?=[^$word]\|$) }{ my @x = ($1, $2); $x[1] =~ s/(.)./$1/g; join '', @x; }xige; }` [download] That matches a complete "word" that consists entirely of doubled characters. The "word" is in $2; $1 holds the preceeding character. In the replacement, since I know that $2 contains only doubled characters, I just delete every other character. (Tested.)	[reply] [d/l]

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Re: (tye)Re: Removing characters
by chipmunk (Parson) on Jan 09, 2001 at 04:03 UTC

my $word = q{-\w'(),};

s{
  (^|[^$word])
  (
   (?:([$word])\3)+
  )
  (?=[^$word]|$)
 }{
  my @x = ($1, $2);
  $x[1] =~ s/(.)./$1/g;
  join '', @x;
 }xige;
}
[download]

[reply]
[d/l]