Re^2: what does this regex do?

It won't match anything, because the '/' is part of the pattern, and is followed by the beginning-of-string anchor.

Caution: Contents may have been coded under pressure.

Comment on Re^2: what does this regex do?

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Re^3: what does this regex do? by muba (Priest) on Nov 07, 2005 at 22:22 UTC
Quote from self: in a `eval` statement probably, I don't know `eval " [...] s${regexpand}foobar/; [...] ";` [download] This code wil validly substitute any of those three words at the beginning of a string and before a word boundary with 'foobar'. I see no reason for doing this but it is perfectly valid. Unless I'm completely wrong of course :p	[reply] [d/l] [select]
Re^4: what does this regex do? by Roy Johnson (Monsignor) on Nov 07, 2005 at 22:26 UTC
Oh, I see. When you said "use this as a regexp", you meant "use part of it as a regexp and part of it as a delimiter." Thanks for clarifying that. Caution: Contents may have been coded under pressure.	[reply]
Re^5: what does this regex do? by muba (Priest) on Nov 07, 2005 at 22:28 UTC
I am sorry I apparently was not clear enough :)	[reply]