in reply to Re^2: minimum, maximum and average of a list of numbers at the same time
in thread minimum, maximum and average of a list of numbers at the same time
He also isn't saving as many comparisons as he thinks.
I've added some counts to the following version of his implementation of the algorithm and where using three passes on 100 elements you would expect 200 comparisions, his code does 198--for a saving of just 2--, but he also does 302 dereferences (which admitedly is traded for allocating stack space for the arg list) and a mod operation.
Maybe the algorithm can be implemented more economically, but quite where the saving comes in escapes me.
#! perl -slw use strict; my( $comps, $mods, $derefs ) = (0)x3; sub min_max_avg { my $ref = shift; my ( $min, $max, $agv, $i ); my ( $current_min, $current_max ); $comps++; $derefs++; $mods++; if ( @{$ref} % 2 == 0 ) { $comps++; $derefs +=4; ( $min, $max ) = $ref->[0] < $ref->[1] ? ( $ref->[0], $ref->[1] ) : ( $ref->[1], $ref->[0] ); $derefs += 2; $agv = $ref->[0] + $ref->[1]; $i = 2; } else { $derefs++; $min = $max = $agv = $ref->[0]; $i = 1; } while ( $i < @{$ref} and ++$comps ) { $comps++; $derefs += 4; ( $current_min, $current_max ) = $ref->[$i] < $ref->[ $i + 1 ] ? ( $ref->[$i], $ref->[ $i + 1 ] ) : ( $ref->[ $i + 1 ], $ref->[$i] ); $comps++; $min = $current_min if ( $current_min < $min ); $comps++; $max = $current_max if ( $current_max > $max ); $derefs += 2; $agv += $ref->[$i] + $ref->[ $i + 1 ]; $i += 2; } $derefs++; return ( $min, $max, $agv / @{$ref} ); } my( $min, $max, $ave ) = min_max_avg [ 1 .. 100 ];; print "$min $max $ave"; print "comps:$comps derefs: $derefs mods: $mods";
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Re^4: minimum, maximum and average of a list of numbers at the same time
by LucaPette (Friar) on Nov 10, 2005 at 17:04 UTC | |
by BrowserUk (Patriarch) on Nov 10, 2005 at 17:38 UTC | |
by salva (Canon) on Nov 11, 2005 at 15:12 UTC | |
by BrowserUk (Patriarch) on Nov 11, 2005 at 16:37 UTC |