in reply to Re: CarTalk Puzzler
in thread CarTalk Puzzler
print sqrt==int(sqrt)?1:0for 1..2e4;
:-)
You got away with it because perl is looking for an expression; when the thing it then sees starts with a digit, it can't be anything but a literal number. So the parser eats as many characters as can be part of a literal number and then stops. For some fun, insert an x right after the 0 and watch what happens; or try any number of underscores.
Makeshifts last the longest.
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Re^3: CarTalk Puzzler
by Perl Mouse (Chaplain) on Nov 18, 2005 at 14:01 UTC | |
by Aristotle (Chancellor) on Nov 18, 2005 at 14:05 UTC |