Re^2: Executing programs without waiting

Here's what I'm trying now:

#!/usr/bin/perl

$SIG{CHLD} = "IGNORE";
fork();
exec("perl set");

Is this right? The first program still doesn't seem to continue until the child program finishes... What am I missing here?

Comment on Re^2: Executing programs without waiting

Replies are listed 'Best First'.
Re^3: Executing programs without waiting by andyford (Curate) on Nov 22, 2005 at 22:14 UTC
Unfortuately, fork is a bit more complicated. This should help you: http://www.oreilly.com/openbook/cgi/ch10_10.html	[reply]
Re^4: Executing programs without waiting by gcoates (Novice) on Nov 22, 2005 at 22:28 UTC
Ah, that explains it. It's working for me now. Thanks very much!	[reply]