Re^14: Perl OO and accessors

I can't see any advantage to having them as variables. Can you?

  $ echo "'$RANDOM' is a random number"
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Perl --((8:>*

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Re^15: Perl OO and accessors by fergal (Chaplain) on Dec 01, 2005 at 00:58 UTC
Is that supposed to be an argument for having them as variables? If Bash had a function named random rather than a variable then you could do this `echo "'$(random)' is a random number"` [download] If the extra ()s are too much of a burden then the logical conclusion is that everything should be a variable just to make it easy to do in string interpolation. The principle of least surprise means that you shouldn't make something look like a variable if it's not going to behave like one. For example `MINUTES=5 echo $MINUTES # 5 SECONDS=5 echo $SECONDS # 1276` [download] How can that be a good thing? There's not even a warning. Also, having variables that aren't leads to run time errors that could have been caught at compile time. If random was a function, attempting to assign to it would be an error (at runtime in bash but at compile time in perl).	[reply] [d/l] [select]

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Re^15: Perl OO and accessors
by fergal (Chaplain) on Dec 01, 2005 at 00:58 UTC

echo "'$(random)' is a random number"
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If the extra ()s are too much of a burden then the logical conclusion is that everything should be a variable just to make it easy to do in string interpolation.

The principle of least surprise means that you shouldn't make something look like a variable if it's not going to behave like one. For example

MINUTES=5
echo $MINUTES
# 5
SECONDS=5
echo $SECONDS
# 1276
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How can that be a good thing? There's not even a warning.

Also, having variables that aren't leads to run time errors that could have been caught at compile time. If random was a function, attempting to assign to it would be an error (at runtime in bash but at compile time in perl).

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