in reply to Howto direct an output filehandle into directory?

Quickly looking at your code:

  • You use different variable names for something that I think is the same thing: my  $OUTFILE_fname = $file.".html"; and result_dir/$OUTFILE_file_name
  • Maybe result_dir should be $result_dir?



    I think you should:

  • use warnings
  • use strict

    Dodge This!