Anonymous Monk has asked for the wisdom of the Perl Monks concerning the following question:
I need to calculate 24 hours ago for localtime as the string Day, time date, etc in text format.
I can remove people from the database 5 minutes of age but I cannot remove people that are 24 hours old. For some reason, it held the number of people for the first day just fine. But now it jumped down to less people than appear in the db that stores the past 5 minutes.
Something is wrong.. still.. and I am getting frustrated. I NEED users to be in day_time for 24 hours and I NEED users to be in now_time for 5 minutes.
Would it be easier to calculate TODAY as opposed to past 24 hours? For example, it will restart every day at midnight server time? If so, how would I do that?
This is my code.
$minutes = $minutes * 60; # minutes = 5 prior my $shorttime = localtime( time() - $minutes ); my $data = qq(DELETE FROM now_time WHERE time < "$shorttime"); my $sth = $dbh->prepare($data); $sth->execute() or die $dbh->errstr; #my $day = 60 * 60 * 24; #my $timeday = $timenow - $day; my $day = localtime( time() - 24*60*60 ); my $data = qq(DELETE FROM day_time WHERE time < "$day"); my $sth = $dbh->prepare($data); $sth->execute() or die $dbh->errstr;
|
|---|
| Replies are listed 'Best First'. | |
|---|---|
|
Re: calculating 24 hours ago with localtime
by McDarren (Abbot) on Dec 09, 2005 at 07:54 UTC | |
by Anonymous Monk on Dec 09, 2005 at 08:07 UTC | |
by McDarren (Abbot) on Dec 09, 2005 at 08:28 UTC | |
|
Re: calculating 24 hours ago with localtime
by svenXY (Deacon) on Dec 09, 2005 at 09:15 UTC | |
by b10m (Vicar) on Dec 09, 2005 at 14:07 UTC | |
|
Re: calculating 24 hours ago with localtime
by Delusional (Beadle) on Dec 09, 2005 at 13:49 UTC | |
|
Re: calculating 24 hours ago with localtime
by TedPride (Priest) on Dec 09, 2005 at 16:28 UTC |