Re: Quick Regex question

wouldn't a split just do it???

@pathtofile = split(/\\/, $path);
$file =  pop(@pathtofile);

$path here can be parsed from the form
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Re: Re: Quick Regex question by Corion (Patriarch) on Jan 14, 2001 at 01:46 UTC
A split will only work, if the filename is delimited by a backslash ('\'). Under DOS/Windows, there is still the nasty and often overlooked possibility of having a filename like `c:myfile.ext`, which is a valid filename, meaning a file on the drive `c:` in the current directory for drive `c:`. So the split should at least be on `[\\:]`, but if we want real portability, I second the use of File::Basename, which is in the standard Perl distribution.	[reply]

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Re: Re: Quick Regex question
by Corion (Patriarch) on Jan 14, 2001 at 01:46 UTC

A split will only work, if the filename is delimited by a backslash ('\'). Under DOS/Windows, there is still the nasty and often overlooked possibility of having a filename like c:myfile.ext, which is a valid filename, meaning a file on the drive c: in the current directory for drive c:.

So the split should at least be on [\\:], but if we want real portability, I second the use of File::Basename, which is in the standard Perl distribution.

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