Understandig on Creating Empty array reference

jesuashok has asked for the wisdom of the Perl Monks concerning the following question:

Hi All monks

I have a doubt in creating a empty array reference.

#!/usr/local/bin/perl
                                                                      
+                                                       
@d = ( 1,2);
$array = \@d;
$array = \();
$$array[0] = 1;
                                                                      
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print "Value :", $$array[0] , "\n";
[download]

In the above code

If I comment "$array = \@d;" then If I run the code I am getting an error like

<bold>Not an ARRAY reference</bold>

Can't I create Empty array reference.

Or am I am making any mistake in understanding the array reference

Please adive me on the same.

Thank you all

"Keep pouring your ideas"

Comment on Understandig on Creating Empty array reference Download Code

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Re: Understandig on Creating Empty array reference by Corion (Patriarch) on Dec 16, 2005 at 09:21 UTC
`\()` does not create an array reference. See `perldoc perlop` on the `\` operator to see what it does. What you want is: `$array = []` [download]	[reply] [d/l] [select]
Re: Understandig on Creating Empty array reference by davido (Cardinal) on Dec 16, 2005 at 09:23 UTC
A doubt would be tendancy toward disbelief. What you have is a question. `$array = \();` doesn't create a reference to an empty array. You probably want `$array = [];` `\()` creates individual references to each entity inside of the `()`. Since there is no entity inside of your `()`, no reference is created. `[]` is the anonymous array constructor. That's what you're looking for. Dave	[reply] [d/l] [select]