in reply to Finally, C

Is there any way, in Perl, to create an alias to a lexical?
Yes, but it requires a trick: 
my $foo = "foo";
for my $bar ($foo) {$bar = "bar"}
print $foo;
__END__
bar

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And there's the @_ trick you already mentioned. There are also a couple of constructs that allow you to alias a variable to $_.
Lexicals seem very different to me from anything there's in C, am I wrong?
Maybe, depending on what you are asking. If you mean that variables are implemented different than in C, yes, you are right. If you are referring to what differs a (Perl) lexical variable from a (Perl) package variable, and want to know how this differs from the C equivalent, then there's no real answer. In C, all variables are lexical - there's no such thing as name spaces in C.
Perl --((8:>*

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Re^2: Finally, C
by QM (Parson) on Dec 16, 2005 at 23:56 UTC
    This also demonstrates that the for variable is an alias, and not a copy: 
    my $foo = "foo";
for my $bar ($foo) 
{
    print "foo: $foo, ", \$foo, "\n";
    print "bar: $bar, ", \$bar, "\n";
    $bar = "bar";
    print "foo: $foo, ", \$foo, "\n";
    print "bar: $bar, ", \$bar, "\n";
}

print "foo: $foo, ", \$foo, "\n";
__OUTPUT__
foo: foo, SCALAR(0x18245f0)
bar: foo, SCALAR(0x18245f0)
foo: bar, SCALAR(0x18245f0)
bar: bar, SCALAR(0x18245f0)
foo: bar, SCALAR(0x18245f0)
__END__

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    -QM
    --
    Quantum Mechanics: The dreams stuff is made of

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