Re^2: Understanding order of module compilation and execution

So, if the script has "use A;" before "use B;", the compiler will complile "A" first (and during that compilation, it will compile any 'used' modules in A), then, when it has compiled A, it will compile B.

Not quite. The compiler may *start* compliling "A" first, but it will not necessary compile all of "A" first. Even without using circular references.

# main.pl
use ModA;
use ModB;
# prints B A
1;
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# ModA.pm
package ModA;
use ModB;
print("A\n");
1;
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# ModB.pm
package ModB;
print("B\n");
1;
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Re^3: Understanding order of module compilation and execution by Perl Mouse (Chaplain) on Dec 16, 2005 at 18:06 UTC
The compiler may start compliling "A" first, but it will not necessary compile all of "A" first. What do you think my and during that compilation, it will compile any 'used' modules in A means? `Perl --((8:>*`	[reply]
Re^4: Understanding order of module compilation and execution by ikegami (Patriarch) on Dec 16, 2005 at 20:01 UTC
I missed that somehow, or misinterpreted it. It's definitely does not specify at which point during the compilation of 'A' those modules are compiled, so take my post as clarification.	[reply]