Re: accessing array through array reference in hash

I think you need curly braces around $hash{'aref'} to explicitly cast it as an array. (Not sure if my terminology is correct.)

#!/usr/local/bin/perl -w
use strict;

my @array = ('one','two','three');
my $aref = \@array;
my %hash = ();
$hash{'aref'} = $aref;
print "Array length is:", scalar(@{$hash{'aref'}}), " \n";
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Array length is: 3
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No good deed goes unpunished. -- (attributed to) Oscar Wilde

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Re^2: accessing array through array reference in hash by phaylon (Curate) on Dec 29, 2005 at 00:27 UTC
Yep, one could try to memorize that @$ dereferences act on the first part of the expression, namely the '$hash' part. If you want to dereference more than the first part, you enclose it in curlies. perldoc perlref knows more about this. Ordinary morality is for ordinary people. -- Aleister Crowley	[reply]