Re: No effect with SIG{INT}

Now I have the problem that SIG{INT} = \&close() is executed at the beginning of the program. I'm using an object now, so when Ctrl-C is pressed this object has to be closed properly, like:

#main
$obj = DBConnect->new ;
$SIG{INT} = \&close ;
....
....

sub close {
     $obj->close ;
     exit ;
}
[download]

Any suggestions why this is wrong ?

Luca

Comment on Re: No effect with SIG{INT} Select or Download Code

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Re^2: No effect with SIG{INT} by borisz (Canon) on Jan 16, 2006 at 13:38 UTC
your example work. And close is NOT called. I guess you wrote `$SIG{INT} = \&close();` that line call close. You want `$SIG{INT} = \&close`. `$SIG{INT} = \&close(); # wrong $SIG{INT} = \&close; # ok` [download] Boris	[reply] [d/l]
Re^2: No effect with SIG{INT} by ysth (Canon) on Jan 17, 2006 at 01:18 UTC
To amplify on what borisz said, `\&close()` is a reference to the value returned by close(), while `\&close` is a reference to sub close (which need not have already been defined).	[reply] [d/l] [select]