Re^2: Preserve the value of original array

Thanks, Darren :)

I need to copy the array into an array, and not make a copy of the reference, as in:

sub second {
   my $num_ref = shift;
   my $copy_of_ref = $num_ref;

   push(@$copy_of_ref, 6);

   my $sum = 0;

   foreach (@$copy_of_ref) {
      $sum += $_;
   }

   return $sum;
}
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Am I right?

Comment on Re^2: Preserve the value of original array Download Code

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Re^3: Preserve the value of original array by McDarren (Abbot) on Feb 14, 2006 at 06:20 UTC
Yes, that's fine. But please also take note of bobf's comments below :) Update:Actually, I misread what you said there. Either way is okay. You can either take a copy of the reference, or dereference it into another array. But again, as bobf already pointed out in his update - the simplest way is to just pass the array (rather than a reference) - and then take a copy of that.	[reply]