Anonymous Monk has asked for the wisdom of the Perl Monks concerning the following question:
$k[0] = "a" ; $k[1] = "b"; $k[2] = "c" ;
Uhh, how do I access this in a generic way ?$my_hash_ref->{$k[0]}->{$k[1]}->{$k[2]} ;
|
|---|
| Replies are listed 'Best First'. | |
|---|---|
|
Re: I have a hash in a hash in a .....
by Roy Johnson (Monsignor) on Feb 21, 2006 at 15:30 UTC | |
|
Re: I have a hash in a hash in a .....
by ikegami (Patriarch) on Feb 21, 2006 at 15:29 UTC | |
by brian_d_foy (Abbot) on Feb 21, 2006 at 20:14 UTC | |
by ikegami (Patriarch) on Feb 21, 2006 at 20:37 UTC | |
by brian_d_foy (Abbot) on Feb 21, 2006 at 20:50 UTC | |
by ikegami (Patriarch) on Feb 21, 2006 at 20:57 UTC |