in reply to When is a function call not a function call

To make it work I need to resort to: 
print sort grep {1} uniq 0,0,1,2;

I know it's mentioned in the node that Roy Johnson linked to, but I think it bears repeating that you don't need to resort to such arcane chicanery. Simply adding parentheses does the trick: 

print sort(uniq(0,0,1,2));

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duff

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Re^2: When is a function call not a function call
by dpuu (Chaplain) on Mar 30, 2006 at 04:52 UTC
    That doesn't seem to work: 
    %  perl -we 'sub fn {print "$a$b\n"} print(sort(fn(0,0,1,2)))'
Unquoted string "fn" may clash with future reserved word at -e line 1.
00
10
21
0012

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    I can eliminate the warnings by choosing a function name that isn't all-lowercase but, as the output demonstrates, the function is still called as a comparator, not a modifier of the input list.

    Update: I was using perl 5.6.1. The parentheses trick works with 5.8.

    --Dave
    Opinions my own; statements of fact may be in error.
[reply]
[d/l]

      It's good to know that 5.6.x is broken in this regard in case one of us is unlucky enough to be required to use a 5 year old perl distribution. :-)

      thanks

      duff

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