Re: Regular expression question

My interpretation of your question:

"I want to extract everything contained within the first pair of parentheses in the given string"

In that case....

#!/usr/bin/perl -w
use strict;

my $string = "Identities = 1529/1540 (99%), Gaps = 2/1540 (0%)";
my ($wanted) = $string =~ m#\((.*?)\)#;
print "$wanted\n";
[download]

That outputs 99%, but it may need to be tightened up a bit depending on how accurate my interpretation of your question is, and how much your data varies.

Comment on Re: Regular expression question Download Code

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Re^2: Regular expression question by rangersfan (Novice) on Mar 31, 2006 at 07:40 UTC
what does the m# do? m is for match, but I don't understand what the # does.	[reply]
Re^3: Regular expression question by gube (Parson) on Mar 31, 2006 at 07:50 UTC
Hi rangersfan, (/) This is the usual delimiter for the text part of a regular expression. you can also use (#) as delimiter. By using usual delimiter with regexp i have given the code below you can also refer that for your understand :-p	[reply]
Re^4: Regular expression question by rangersfan (Novice) on Mar 31, 2006 at 07:52 UTC
learn something new everyday.... thanks!	[reply]
Re^5: Regular expression question by johngg (Canon) on Mar 31, 2006 at 08:59 UTC