hi everybody.

i have a slight problem here.

my task involve calling c from perl which inturn has perl embedded in it.

this is my c code which i call 1.c

#include <EXTERN.h> 
#include <perl.h> 
 
static PerlInterpreter *my_perl; 
int main(int argc, char **argv, char **env) 
{ 
    char *myargv[] ={"","Random.pl"}; 
PERL_SYS_INIT3(&argc,&argv,&env); 
my_perl=perl_alloc(); 
 
perl_construct(my_perl); 
PL_exit_flags |= PERL_EXIT_DESTRUCT_END; 
perl_parse(my_perl,NULL,argc,myargv,(char**)NULL); 
perl_run(my_perl); 
perl_destruct(my_perl); 
perl_free(my_perl); 
PERL_SYS_TERM(); 
}
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this is my random.pl

    

package cryzone; 
 
 
print "Hello"; 
 
print " i am in random"; 
 
print $cryzone::a; 
 
1;
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this is my file test.pl from which i call 1.exe

use cryzone; 
$cryzone::a=1; 
print $cryzone::a; 
system("1.exe"); 
$cryzone::a=2; 
print $cryzone::a;
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and this is my package cryzone

package cryzone; 
$a=0; 
1;
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on running i am never able to access $cryzone::a inside random.pl even though ihave declared it as belonging to cryzone.

how can this be solved.

the output is

1Hello i am in random2

whereas the desired output is

1Hello i am in random12

please help me.

Edited by planetscape - added code tags around output