Please be kind. For I am a stranger to the World of JAPHs. Here is my first JAPH. 
#! /usr/bin/perl
$a = "a";;foreach $n (1 .. 26){$hash{$n} = $a;;$a++;
}$code = '01010.10101.10011.10100..00001.01110.01111
.10100.01000.00101.10010..10000.00101.10010.01100.
.01000.00001.00011.01011.00101.10010';;@array= split
( /\.\n*/, $code );;foreach $n ( 0 .. $#array ) { if
($array[$n] ne ""){@letter=split( /\s*/,$array[$n]);
$num=convert();$japh.=$hash{$num};}else{$japh.=" ";}
}$japh =~ s/\b([a-z])/\U\1/g;; print $japh,"\n";;sub
convert{$tot = 0;;if ( $letter[0] ){ $tot += 16;}if(
$letter[1]){$tot+=8; } if ($letter[2]){$tot += 4;}if
( $letter[3] ){ $tot+=2;} if ( $letter[4]){$tot+=1;}
return $tot;}

[download]
Teach me, oh great Obfuscators, for I am ready to learn. - kel -

Replies are listed 'Best First'.
Re: My First JAPH
by c-era (Curate) on Jan 25, 2001 at 02:49 UTC
    This is a good first try. Here are a few hints to help you out.
    1 - Use $_, @_, and %_ as much as possible, also don't use long or descriptive variable names.
    2 - Try to use math expressions instead of plain numbers.
    3 - Use trinary instead of if if possible.
    4 - Try using some evals, this lets you hide your code.

    Below is an example of how you could have worked this to make it more obfuscated. 

    # You may want to change the name of $a
$a = "a";

# Don't use a simple number, make a math statement instead
# Remember that $a++ will increment after the expression is
# evaluated. I used %_ as the hash to add some confusion
for (1 .. (6/3*10+15/2.5)){$_{$_} = $a++;}

# You may want to write a piece of code that generates
# this string to hide things a bit more
$c = '01010.10101.10011.10100..00001.01110.01111
.10100.01000.00101.10010..10000.00101.10010.01100.
.01000.00001.00011.01011.00101.10010';

# Using @_ to add some more confusion
@_= split( /\.\n*/, $c );

# Reuse $a and put your sub in it. Note the use of >>
# instead of multiple if statements
$a = sub {$c = 0; for (0..$#_){$c+=(16>>$_) if $_[$_];}$c;};

foreach ( 0 .. $#_ ) { 

# Replace your if statement with trinary, dereferance $a to call your 
+sub
    $japh.=($_[$_] ne "")?$_{&$a(split(/\s*/,$_[$_]))}:" ";
}

$japh =~ s/\b([a-z])/\U\1/g;
print $japh,"\n";

# Here is it squished together.
$a="a";for(1..(6/3*10+15/2.5)){$_{$_}=$a++;}
$c='01010.10101.10011.10100..00001.01110.01111
.10100.01000.00101.10010..10000.00101.10010.01100.
.01000.00001.00011.01011.00101.10010';
@_=split(/\.\n*/,$c);$a=sub{$c = 0;
for(0..$#_){$c+=(16>>$_)if$_[$_];}$c;};
foreach(0..$#_){$japh.=($_[$_]ne"")?
$_{&$a(split(/\s*/,$_[$_]))}:" ";}
$japh =~ s/\b([a-z])/\U\1/g;
print $japh,"\n";

    [download]
    I hope this helps you.
[reply]
[d/l]
      Definitely!! Thanks. I have to look up trinary operators but I think I understand the basic gist of them. - kel -
[reply]

Back to Obfuscated Code