in reply to Which is the efficient pattern matching modifiers (s///g; or s///gs;)?

If you'd bother to read perlre it quite clearly states that the only thing the /s modifier does is change the meaning of a "." to also match a \n character. That's in no way going to affect performance meaningfully.

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Re^2: Which is the efficient pattern matching modifiers (s///g; or s///gs;)?
by perlsen (Chaplain) on Apr 13, 2006 at 13:10 UTC
    Ohh!!..ok.
    Thanks for your great suggetions.

    regards,
    perlsen