in reply to Re^2: Equality operators
in thread Equality operators
Others have already explained how the conversion works, but if you want to see for yourself the number into which a string is coerced, add 0 to the string.
print(0+'a', "\n"); # 0 print(0+'b', "\n"); # 0 print(0+'1', "\n"); # 1 print(0+'2', "\n"); # 2 print(0+'1foo', "\n"); # 1 print(0+'foo1', "\n"); # 0
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